How to get python to recognize each elemant as an integer?

Author Name Status Posted Time Dolphi Powers 3/24/2008 4:59:16 AM Author is Offline Hi all,  i'm having a mental block can anyone help me out if i have a list like this num = ['1;3;2;3;2;1;4', '\n', '30;2;13;2;1;4;2', '2;3;2;1;4;2;4', '3;2;1;4;2;4;1', '2;1;4;2;4;1;4', '1;4;2;4;1;4;2'] How to get python to recognize each elemant as an integer so that i can sum each list that is have it print 16 \n 54 18 etc Thanks in advance

Subject Author Status Date Re: How to get python to recognize each elemant as an integer? Samson Reid 3/25/2008 12:15:13 AM Code: ( python ) >>> num = ['1;3;2;3;2;1;4', '\n', '30;2;13;2;1;4;2', '2;3;2;1;4;2;4', '3;2;1;4;2;4;1', '2;1;4;2;4;1;4', '1;4;2;4;1;4;2'] >>> s = '\n'.join([str(result) for result in [sum([int(i) for i in item.split(';')]) for item in num if item != '\n']]) >>> s '16\n54\n18\n17\n18\n18' >>> print s 16 54 18 17 18 18 >>> Post Comments Re: It works well Dolphi Powers 3/25/2008 12:17:15 AM Samson, It works well, but i'm trying to keep a blank line if the '\n' was there to begin with, how can i tweak that so the solution would have been '16\n\n54\n18\n17\n18\n18' thanks Post Comments Re: See these codes Samson Reid 3/25/2008 12:18:09 AM Code: ( python ) results = [] for item in num:     if item == '\n':         results.append('')     else:         results.append(str(sum([int(i) for i in item.split(';')]))) print '\n'.join(results) Code: ( text ) >>> 16   54 18 17 18 18 >>> print repr('\n'.join(results)) '16\n\n54\n18\n17\n18\n18' >>> I got carried away with the list comprehension in my previous post. s could be: Code: ( python ) s = '\n'.join([str(sum([int(i) for i in item.split(';')])) for item in num if item != '\n']) Post Comments Re: Thanks for breaking it up Dolphi Powers 3/25/2008 12:19:03 AM Hey Smasopn, Thanks for breaking it up onto many lines, i'm so fresh at this that when it's all squeezed into one line my mind breaks Post Comments

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